Honors Precalculus:
Deriving the Quadratic Formula by
Completing the Square
Mt Lebanon HS 2004-5
David Kosbie
Given: ax² + bx + c = 0
Prove: x = (-b ± Ö(b²
- 4ac)) / 2a
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Step |
Reason |
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ax² + bx + c = 0 |
1. Given |
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x² + (b/a)x + (c/a) = 0 |
2. Divide by a |
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Set d = b/(2a) |
3. First step in completing the square |
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(x + d)² = (x + b/(2a))² |
4. Substitute step 3 |
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(x + b/(2a))² = x² + (b/a)x + b²/(4a²) |
5. FOIL |
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x² + (b/a)x + b²/(4a²) = (x + b/(2a))² |
6. Reverse order from step 5 |
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x² + (b/a)x = (x + b/(2a))² - b²/(4a²) |
7. Subtract b²/(4a²) |
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(x + b/(2a))² - b²/(4a²) + (c/a) = 0 |
8. Substitute step 7 into step 2. |
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(x + b/(2a))² + (c/a) = b²/(4a²) |
9. Add b²/(4a²) |
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(x + b/(2a))² = b²/(4a²) – (c/a) |
10. Subtract (c/a) |
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= b²/(4a²) – (4ac)/(4a²) |
11. Multiply (c/a) by (4a)/(4a) to get a common denominator |
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= (b² – 4ac)/(4a²) |
12. Combine numerators |
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(x + b/(2a)) = ±Ö((b² – 4ac)/(4a²)) |
13. Take square root |
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= ±Ö(b² – 4ac)/ Ö(4a²) |
14. Ö(a/b) = Öa / Öb |
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= ±Ö(b² – 4ac)/ (2a) |
15. Ö(4a²) = 2a |
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x = -(b/(2a)) ± Ö(b² – 4ac)/ (2a) |
16. Subtract b/(2a) |
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= (-b ± Ö(b² - 4ac)) / 2a |
17. Combine numerators |
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Q.E.D. |
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